VFD Energy Savings Calculator

Estimate energy and cost savings by implementing Variable Frequency Drives

VFD Energy Savings Calculator

Optimize your motor's energy consumption

Results:

Daily Energy Savings (kWh): 0.00

Daily Cost Savings ($): 0.00

Monthly Energy Savings (kWh): 0.00

Monthly Cost Savings ($): 0.00

Annual Energy Savings (kWh): 0.00

Annual Cost Savings ($): 0.00

Power Reduction (%): 0.00

How to Use the Calculator

Input Motor Details

  1. Enter the motor's rated power in kilowatts (kW).
  2. Specify the daily operating hours for the motor.
  3. Input the number of operating days per year.

Energy Cost & Frequencies

  1. Provide your local energy cost per kilowatt-hour ($/kWh).
  2. Enter the motor's current operating frequency (Hz).
  3. Input the desired reduced operating frequency (Hz) with VFD.

Calculate & Analyze

  1. Click "Calculate Savings" to see results.
  2. View estimated annual energy and cost savings.
  3. Understand the percentage of power reduction achieved.

VFD Energy Savings Fundamentals

Affinity Laws

VFDs save energy by reducing motor speed, which significantly reduces power consumption for centrifugal loads (pumps, fans). This relationship is governed by the affinity laws:

  • Flow is proportional to speed.
  • Pressure is proportional to the square of speed.
  • Power is proportional to the cube of speed.

VFD Benefits

  • Significant energy cost reduction.
  • Improved process control and stability.
  • Reduced mechanical stress on equipment.
  • Lower maintenance costs and extended equipment life.

Key Formula for Power Reduction:

Preduced = Poriginal × (freduced / foriginal)3

Annual Cost Savings:

Savings = (Poriginal - Preduced) × Operating Hours × Cost/kWh

Calculation Formulas

Power Reduction Ratio:
Ratio = (freduced / foriginal)3

Reduced Power (kW):
Preduced = Poriginal × Ratio

Annual Energy Savings (kWh):
Esavings = (Poriginal - Preduced) × Hours/Year

Annual Cost Savings ($):
Csavings = Esavings × Cost/kWh

Example Calculation

Consider a 10 kW motor operating 12 hours/day, 300 days/year, with an energy cost of $0.15/kWh. If the frequency is reduced from 60 Hz to 45 Hz:

Poriginal = 10 kW

foriginal = 60 Hz, freduced = 45 Hz

Ratio = (45 / 60)3 = (0.75)3 = 0.421875

Preduced = 10 kW × 0.421875 = 4.21875 kW

Power Savings = 10 - 4.21875 = 5.78125 kW

Annual Operating Hours = 12 hours/day × 300 days/year = 3600 hours/year

Annual Energy Savings = 5.78125 kW × 3600 hours = 20812.5 kWh

Annual Cost Savings = 20812.5 kWh × $0.15/kWh = $3121.88

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